Write a function called PrintToZero that takes in a reference parameter num. The function prints out the content of num up to zero. For example, if *num = 10, then PrintToZero(num) prints 10 9 8 7 .... 0.
C programming?
I'll include code for CheckTotalASCII in this one...I had to cancel the response in the other post you made and now I can't post another answer.
#include %26lt;stdio.h%26gt;
void PrintToZero(int num)
{
printf("%i ", num);
if (num)
PrintToZero(num-1);
}
char CheckTotalASCII(char * pString)
{
int result = 0;
while (*pString)
result += *pString++;
return (result %26amp; 1) ? 'O' : 'E';
//return "EO"[result %26amp; 1]; %26lt;- slightly more effiecient
}
Reply:printtozero(int n)
{
for(;n%26gt;=0;n--)
{
cout%26lt;%26lt;n;
}
}
Reply:#include%26lt;stdio.h%26gt;
void PrintToZero(int *num)
{
int val = *num;
for(val %26gt;= 0; val--)
printf("\t%d",val);
}
sage
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